## Free drug concentration

Discussion of all aspects of biological molecules, biochemical processes and laboratory procedures in the field.

carbonp
Garter
Posts: 7
Joined: Tue Oct 13, 2009 11:35 pm

### Free drug concentration

If,
Free protein = [(Total protein - Total drug -Dissociation constant)] (+/-) under root of (Total protein - Total drug -Dissociation constant)^2 + 4 (dissociation Constant * Total Protein) divided by 2
If Total protein - 0.035 g /microliter,
Total drug - 3319.246 x 10^-15 moles/l (Molecular weight of drug - 337.41 g/mole)
Dissociation constant = 0.27 nM,
How to calculate the free protein, Above is quadratic equaltion,
As the unit dissociation constant of drug is in nM, while that of total protein and total drug is in different units, How to calculate the free protein ?

Is there any way to convert 0.27 nM in to some other unit that can be used for calculation?

JackBean
Inland Taipan
Posts: 5694
Joined: Mon Sep 14, 2009 7:12 pm

### Re: Free drug concentration

First of all, I don't think, you are supposed to substract the diss. const. from the protein amount
http://www.biolib.cz/en/main/

Cis or trans? That's what matters.

carbonp
Garter
Posts: 7
Joined: Tue Oct 13, 2009 11:35 pm
Sorry its addition of dissociation constant. but formula does not say multiplication of dissociation constant.

JackBean
Inland Taipan
Posts: 5694
Joined: Mon Sep 14, 2009 7:12 pm
Sorry, I don't get it.
Anyway, it doesn't make much sense to substract/add the dissociation constant from/to protein/drug amount
http://www.biolib.cz/en/main/

Cis or trans? That's what matters.

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