## Beer Lambert’s Law help..:(

**Moderators:** honeev, Leonid, amiradm, BioTeam

### Beer Lambert’s Law help..:(

Okay, guys need your help soo please help if you can

I know the equation, I know what to do.. it’s just the units and things.

Here are my concentrations 0.080, 0.040, 0.020, 0.010 and 0.005

I received absorbance readings for these (in 340nm)

Plotted against time (minutes)

Still all cool..

Found the gradient from the graph (mol/min/L)

Now I need to use the “Beer Lambert’s Law” to convert the gradient to velocity using the equation from this law (A= ECL)

(I think I know the steps, but really stuck on the units..but not too sure on the equation calculation anyway)

Please help…

I know the equation, I know what to do.. it’s just the units and things.

Here are my concentrations 0.080, 0.040, 0.020, 0.010 and 0.005

I received absorbance readings for these (in 340nm)

Plotted against time (minutes)

Still all cool..

Found the gradient from the graph (mol/min/L)

Now I need to use the “Beer Lambert’s Law” to convert the gradient to velocity using the equation from this law (A= ECL)

(I think I know the steps, but really stuck on the units..but not too sure on the equation calculation anyway)

Please help…

*Love, Peace & Freedom..*

Your concentrations are in mol/l?

What do you mean by gradient?

Instead of mol/min/l use mol/(l.min) or mol/l/min. You may use M instead of mol/l, thus you get M/min (i.e. increase of concentration per minute).

But I guess, what you read from graph is ABS/min, isn't it?

What do you mean by gradient?

Instead of mol/min/l use mol/(l.min) or mol/l/min. You may use M instead of mol/l, thus you get M/min (i.e. increase of concentration per minute).

But I guess, what you read from graph is ABS/min, isn't it?

http://www.biolib.cz/en/main/

*Cis*or*trans*? That's what matters.-
- Viper
**Posts:**442**Joined:**Fri Feb 15, 2008 5:38 pm**Location:**Philomath, Oregon, USA

### Re: Beer Lambert’s Law help..:(

Nice, Jack.

For units, I'd add that you will need the path length for your spectrophotometer and the length unit from your extinction coefficient (hopefully these will match). The most likely light path length though your sample is 1 cm (if the spectrometer/colorimeter uses a 1 cm cell). Extinction coefficients are most commonly reported as 1/(M * cm), so when they are multiplied by a concentration (M) and a path length (cm) they become a unitless absorbtion.

For units, I'd add that you will need the path length for your spectrophotometer and the length unit from your extinction coefficient (hopefully these will match). The most likely light path length though your sample is 1 cm (if the spectrometer/colorimeter uses a 1 cm cell). Extinction coefficients are most commonly reported as 1/(M * cm), so when they are multiplied by a concentration (M) and a path length (cm) they become a unitless absorbtion.

### Re: Beer Lambert’s Law help..:(

The path lenght is 1 cm

The molar extinction co efficient is 6220 l/mol/cm at 340 nm

Stuck

The molar extinction co efficient is 6220 l/mol/cm at 340 nm

Stuck

*Love, Peace & Freedom..*

So for each of your point you know A (absobance), E (coefficient of absorbance) and L (path length) and you have problem calculating C (concentration)?

I remind you if you put A in Absorbance/min, then C will be expressed in M/min

I remind you if you put A in Absorbance/min, then C will be expressed in M/min

Patrick

Science has proof without any certainty. Creationists have certainty without

any proof. (Ashley Montague)

Science has proof without any certainty. Creationists have certainty without

any proof. (Ashley Montague)

### Re: Beer Lambert’s Law help..:(

Yep, that's it:)

Finding the concentation..the equation has to be arranged. Which I have:)

I'm just not sure of the calculation steps.. (to find C)

Finding the concentation..the equation has to be arranged. Which I have:)

I'm just not sure of the calculation steps.. (to find C)

*Love, Peace & Freedom..*

### Re: Beer Lambert’s Law help..:(

Absorbance: let's say 0.2744 nm

Extinction: 6220 l/mol/cm

Path lenght (L): 1 cm

0.2744 / 62240 = 4.11

(the 1 get's cancelled out)

now what? what's the next step? using international units of enzymes..

Extinction: 6220 l/mol/cm

Path lenght (L): 1 cm

0.2744 / 62240 = 4.11

(the 1 get's cancelled out)

now what? what's the next step? using international units of enzymes..

*Love, Peace & Freedom..*

### Who is online

Users browsing this forum: No registered users and 7 guests