Drug dissociation constant

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Drug dissociation constant

Post by carbonp » Tue Oct 20, 2009 6:20 pm

1) I need to calculate the concentration represented by one molecule in a animal cell. You should know that typical animal cell is 15 um in diameter and 1 um in thick. You will also remember that avogrado's number is 6 x 10^23.
2) To think about - a rod shaped bacterium is about 1 mm long by 0.5 mm in diameter. What is the concentration of one molecule in this volume.
What would be the Kd (dissociation constant) of a drug need to be bind on molecule in the cell volume that you calculated.

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Inland Taipan
Inland Taipan
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Re: Drug dissociation constant

Post by JackBean » Wed Oct 21, 2009 12:55 am

Well, I'm pretty sure, that we remember Avogadro's number :twisted:
Why don't you calculate it by yourslef? What's the problem?
Maybe try to ASK for help next time. May help :twisted:

Cis or trans? That's what matters.

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