Punett Square Help!!!!

[Jason123456]

I would appreciate any help with this.

On Venus, Blue skin is compltely dominant (B), and green skin is recessive(b). Also, pointed ears are completely dominant(P), and blunt ears are recessive(p). A male Venusian who is heterozygous for BOTH skin color and ear shape mates with a female Venusian who is homozygous dominant for skin color and heterozygous for ear shape.

A: What gametes (the genotypes) are produced by the male?

B: what gametes (the genotypes) are produced by the female?

and c: using a 4x4 punett square, what are the genotypes of the offspring?


Thanks again!!!

[mith]

Write out their genotypes and you should get your answer pretty easily.

[Jason123456]

Write out their genotypes and you should get your answer pretty easily.

With all due respect, if I could get the answer I wouldn't have asked.

BbPp and BBPp are the genotypes.. I don't know how to make a punett sqaure so it's not exactly easy for me to do this problem.

[mith]

You could do a forum search, there's more than 3 worked out examples(including trihybrid crosses)

[Jason123456]

You could do a forum search, there's more than 3 worked out examples(including trihybrid crosses)

All the examples I am seeing on the internet use a mother and father with the same RrYy genotype. Where is the link to the dihybrid cross? Can't seem to find it. I did find some simple 2x2 punett squares, but they are of no help. I need to create a punett square using BbPp x BBPp

What I am looking for is what would go on the X axis and what would go on the Y axis? I could figure it out if I knew that.

[Jason123456]

Awesome.. I just found a punett square calculator

I don't have 5 posts yet so I can't share.. sorry

[Jason123456]

Awesome.. I just found a punett square calculator

I don't have 5 posts yet so I can't share.. sorry

[Jason123456]

there ya go, just in case anyone else wants to play around with it.


http://www.changbioscience.com/genetics/punnett.html

[mith]

viewtopic.php?t=10756&highlight=dihybrid+cross

Well, if you already found hetero X hetero, you could just replace one of the sides with your homozygote and redo the calculation.